(15x^2+10x-5)/(5x+5)
can you show the steps to simplifying
can you show the steps to simplifying
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The answer is 3x-1.
Ok, here are the steps as to how I arrived to my answer:
5 (3x^2 ) + 5 (2x) + 5 (-1)/5x + 5
5 (3x^2 + 2x - 1)/5x + 5
5 (x + 1) (x - 1/3)/5x + 5
5 (x + 1) (3x - 1)/5x + 5
5 (x + 1) (3x - 1)/5 (x) + 5 (1)
5 (x + 1) (3x - 1)/5 (x + 1)
(x + 1) (3x-1)/x + 1
(x + 1) (3x-1)/x + 1 - Reduce the expression by canceling out the common of (x+1) from the numerator and the denominator.
(3x-1)
Answer: 3x-1
Ok, here are the steps as to how I arrived to my answer:
5 (3x^2 ) + 5 (2x) + 5 (-1)/5x + 5
5 (3x^2 + 2x - 1)/5x + 5
5 (x + 1) (x - 1/3)/5x + 5
5 (x + 1) (3x - 1)/5x + 5
5 (x + 1) (3x - 1)/5 (x) + 5 (1)
5 (x + 1) (3x - 1)/5 (x + 1)
(x + 1) (3x-1)/x + 1
(x + 1) (3x-1)/x + 1 - Reduce the expression by canceling out the common of (x+1) from the numerator and the denominator.
(3x-1)
Answer: 3x-1
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There's a really simple way to do this problem. Take the numerator, which is a quadratic function, and factor it into (5x+5)(3x-1). Since (5x+5) is in the numerator now and (5x+5) is in the denominator, you can cancel out these terms, leaving you with the answer of 3x-1.
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(15x^2+10x-5)/(5x+5)
5(3x^2 +2x-1)/5(x+1) [5 is common]
(3x^2+2x-1)/(x+1)
(x+1)(3x-1)/(x+1) [x+1 is common]
= (3x-1)
5(3x^2 +2x-1)/5(x+1) [5 is common]
(3x^2+2x-1)/(x+1)
(x+1)(3x-1)/(x+1) [x+1 is common]
= (3x-1)
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(15x^2 + 10x - 5) = (5x+5)(3x-1)
the (5x+5) cancels with the one below the line, leaving the answer to be 3x-1
the (5x+5) cancels with the one below the line, leaving the answer to be 3x-1