I have this problem on my math homework that looks like this: simplify the cube root of 8x^3y^4
I know you have to "jailbreak" and move all the numbers that appear three times to the outside, bla bla bla. but after that I'm not really sure how to simplify it more. Can you do out the problem on here for me and explain how you did it? (even the jailbreak part b/c if its from the begining i'll understand it better)
Thank you so much! :D
I know you have to "jailbreak" and move all the numbers that appear three times to the outside, bla bla bla. but after that I'm not really sure how to simplify it more. Can you do out the problem on here for me and explain how you did it? (even the jailbreak part b/c if its from the begining i'll understand it better)
Thank you so much! :D
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^3√(8x^3y^4)
with variables, it's division.
here are some examples for you to see how they work:
^3√x^6 = x^ (6/3) = x^2
^4√y^12 = y^(12/4) = y^3
^8√y^25 = ^8√(y^24 times y^1) = y^ (24/8) times ^8√y = y^3 ^8√y
so to proceed with our question.
^3√8x^3y^4
^3√[8x^3y^3 times y^1]
^3√8 times x^(3/3) times y^(3/3) times ^3√y
2 times x^1 times y^1 times ^3√y
2xy ^3√y
with variables, it's division.
here are some examples for you to see how they work:
^3√x^6 = x^ (6/3) = x^2
^4√y^12 = y^(12/4) = y^3
^8√y^25 = ^8√(y^24 times y^1) = y^ (24/8) times ^8√y = y^3 ^8√y
so to proceed with our question.
^3√8x^3y^4
^3√[8x^3y^3 times y^1]
^3√8 times x^(3/3) times y^(3/3) times ^3√y
2 times x^1 times y^1 times ^3√y
2xy ^3√y
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((2^3)*(x^3)*(y^3)*y)^(1/3) = 2*x*y*y^(1/3)