Math simplifying help
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Math simplifying help

[From: ] [author: ] [Date: 11-05-07] [Hit: ]
Simplify.What is the fifth term of a sequence whose first term is 5 and whose common ratio is 3?1,215-The first one. f is to the first power, g to the second.......
Simplify.
(fg^2)^4

Simplify.
(-3ab^3)^4

Simplify.
1.5m^7(-4m^5)^2

Simplify.
(-4a^3)^3•a^4

What is the fifth term of a sequence whose first term is 5 and whose common ratio is 3?
243
405
1,215

-
The first one. f is to the first power, g to the second. Multiply by 4; you get f^4g^8. The second one; the a is to the first power, the b to the 3rd. First take (-3) to the 4th power, which is positive 81. so 81 a^4b^12. Third one. Take the parenthesis to the second power: 16m^10. Now multiply that by the first term; 1.5 times 16 is 24; m^7 times m^10 is m^17, so 24 m^17. the fourth one:take the parenthesis to the 3rd power, so -64 a^9 then times a^4, so -64 a^`13. The last one: the fifth term is 5 times 3 to the fourth power (you are multiplying by 3 four times) so 5.81 is 405.
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