y/ √y+3√x
thank you
thank you
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y / √y+3√x
y (√y-3√x)
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√y+3√x (√y-3√x)
y√y - 3y√x
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y - 9x
y (√y-3√x)
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√y+3√x (√y-3√x)
y√y - 3y√x
------------------------
y - 9x
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(y/√y+3√x)
=(y/√y+3√x)*[(√y-3√x)/(√y-3√x)]
=(y*(√y-3√x))/(y-9x)
=(y√y-3y√x)/(y-9x)
P.S We get y-9x by using a^2-b^2 = (a+b)(a-b)
=(y/√y+3√x)*[(√y-3√x)/(√y-3√x)]
=(y*(√y-3√x))/(y-9x)
=(y√y-3y√x)/(y-9x)
P.S We get y-9x by using a^2-b^2 = (a+b)(a-b)
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By multiplying the numerator & denominator by 'rooty-3rootx'.
P.S-I can't find a way to write the square root symbol on my mobile so I have denoted it with 'root'.
P.S-I can't find a way to write the square root symbol on my mobile so I have denoted it with 'root'.