find ZW and Z/W leave in polar form
z=1-i
w=1-sqrt of 3 i
i is not in the sqrt. thanks!!
z=1-i
w=1-sqrt of 3 i
i is not in the sqrt. thanks!!
-
Let's put them both in polar form first:
z = (√2)(1/√2 - i/√2)
.. = (√2)(cos(-π/4) + isin(-π/4))
|w| = √(1 + 3) = 2
hence
w = 2(1/2 - i(√3)/2)
... = 2(cos(-π/3) + i sin(-π/3))
To multiply, we multiply the moduli and add the arguments.
hence
zw = (2√2)(cos(-7π/12) + i sin(-7π/12))
To divide, we divide the moduli and subtract the arguments.
Note that -π/4 -(-π/3) = π/12
hence
z/w = (√2/2)(cos(π/12) + i sin(π/12))
z = (√2)(1/√2 - i/√2)
.. = (√2)(cos(-π/4) + isin(-π/4))
|w| = √(1 + 3) = 2
hence
w = 2(1/2 - i(√3)/2)
... = 2(cos(-π/3) + i sin(-π/3))
To multiply, we multiply the moduli and add the arguments.
hence
zw = (2√2)(cos(-7π/12) + i sin(-7π/12))
To divide, we divide the moduli and subtract the arguments.
Note that -π/4 -(-π/3) = π/12
hence
z/w = (√2/2)(cos(π/12) + i sin(π/12))