Just one of my math problems I cant figure out, Thanks : )
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Are you looking for a solution?
You have two unknowns ( x and y) but only one equation relating them.
This is not enough information to find a solution.
In fact there are infintiely many psossibilites ..
For example, if x = 1 then y = -8/3
if x = 12 then y = 0
and so on and so on ad infinitum.
But perhaps you are looking for a graph.
-4x + 3y = -12
Add 4x to both sides
3y = 4x - 12
Divide both sides by 3
y = 4x/3 + 4
This you can plot
Your gradient will be 4/3 and your y-intercept will be 4
You have two unknowns ( x and y) but only one equation relating them.
This is not enough information to find a solution.
In fact there are infintiely many psossibilites ..
For example, if x = 1 then y = -8/3
if x = 12 then y = 0
and so on and so on ad infinitum.
But perhaps you are looking for a graph.
-4x + 3y = -12
Add 4x to both sides
3y = 4x - 12
Divide both sides by 3
y = 4x/3 + 4
This you can plot
Your gradient will be 4/3 and your y-intercept will be 4
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That is an equation.
Now if you want to transfer it into linear equation, you would do the following :
-4x +3y=-12
3y=4x-12
y= (4/3)x - 4
which gives you a linear equation whose slope is 4/3 and y intercept -4.
Not sure if that is what you were asking.
Now if you want to transfer it into linear equation, you would do the following :
-4x +3y=-12
3y=4x-12
y= (4/3)x - 4
which gives you a linear equation whose slope is 4/3 and y intercept -4.
Not sure if that is what you were asking.
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I don't understand what your asking.
are you asking for it be put in slope-intercept form, point-slope or what?!
be more specific please(:
are you asking for it be put in slope-intercept form, point-slope or what?!
be more specific please(:
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hmmt.. you have to cancel out the X or Y values by bringing them over to the right.
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It's the equation of a straight line. Were you asked a question about this straight line? What?