If a=(b times c times d)+b then what does b= , what does c= and what does d=

I've long since forgotten my mathematics from school. Does anyone have a formula for each? 3 fomulas? With working please if poss? Thanks!

Again. If a=bcd+b then what does b=, c= and d=?

Question 1.
What does b=
Okay, the equation is a = bcd + b. We want to know what b is so we have to make b the subject. Problem here, is that the b appears twice in two seperate terms. It appears in bcd AND in +b. So, we have factorise out the b from both terms. When we factorise out the b, we get this:
a = b(cd + 1)
Now, the letter b appears only once which is much better. We now want to get b on its own. Looking at the right hand side, we can see that we've got b TIMES (cd+1). Because it's TIMES (cd+1), we can take that whole thing to the other side by DIVIDING by (cd+1). Therefore, we get:
a / (cd+1) = b OR b = a / (cd+1)

Question 2.
What does c=
Okay, again, our equation is a = bcd + b. The c is trapped in the first term but before we deal with that, we have to deal with the second term first which is +b. Because it's a PLUS b, we need to take it to the other side by SUBTRACTING b so we get:
a - b = bcd
Now we've only got 1 term where the c is trapped in. It is being MULTIPLIED with b and d together so we can take that bd together by DIVIDING by bd. So we get:
(a - b)/bd = c OR c = (a - b) / bd

Question 3.
What does d=
The method will work out in the same way as Question 2. Try it!
Your final answer should be:
(a - b)/bc = d OR d = (a - b)/bc


I hope that information helps with your rearranging equations. :)

a=bcd+b
b=a/bcd
c=a-b/bd
d=a-b/bc

all you have to do is to put everything on the other side except for what is ask. and of course, you have to apply the rules when transposing: + becomes negative and vice versa, and multiplication becomes division and vice versa. there's no fomula. you just need to master the basics. :)

a = (bcd) + b
b = (a - b)/cd
c = (a - b)/bd
d = (a - b)/bc

b=a/(cd+1)
c=(a-b)/bd
d=(a-b)/bc