Hi, Could someone solve this equation for me please

s = u*t + 1/2*a*t^2

I want to solve for t and can't figure it out.

It looks like a physics equation, in which case only the plus square root will be used.

a = 1/2 A
b = u
c = -s

Use the quadratic equation.
t = [-b + sqrt(b^2 - 4ac) ]/ (2*a) This a is not the same as the A in your given equation. Again, t can only be a positive number in physics because it stands for time which in our world only goes in 1 direction.

t = [-u + sqrt(u^2 - 4A(-s) ] / (2A)
t = [-u + sqrt(u^2 + 4A(s) ] / (2A)

http://www.wolframalpha.com/input/?i=s+%3D+u*t+%2B+1%2F2*a*t^2+++solve+for+t

ITS SIMPLE PHYSICS QUESTION!!!

S - DISTANCE

T - TIME

U - INITIAL VELOCITY

S=UT+ 1/2 A.T.T

S/U-1/2/ 1/A =

S * - 1 * 1
_ _ _ = T.T

U 2 A


NOW SQUARE ROOT OF LHS WILL GIVE T


I MAY BE WRONG!

s=u*t+1/2*a*t^2
s=t(u+1/2at)
s=t(u+1/2(v-u)/t*t)
s=t(u+1/2(v-u))
s=t(u-1/2u+1/2v)
s=t(1/2u+1/2v)
s=t(1/2(u+v))
t=2s/(u+v)

Its just a quadratic. Rearrange it to look like At^2 + Bt + C = 0

i don't get it