How to simplify this expression

http://i56.tinypic.com/33cm0lg.png

the 5/6 and 2 are exponents

Could someone please help? The answer is 1 / c^1/6 but I can't figure it out
Thanks so much

c(c^(5/6)) / c^2

law of exponents; multiply the bases, add the exponents

[(c^1)(c^5/6)] / c^2

[c^(1+5/6)] / c^2

[c^(6/6 +5/6)] / c^2

c^(11/6) / c^2

law of exponents; divide the bases, subtract the exponents

c^ (11/6 - 2)

c^ (11/6 - 12/6)

c^ (-1/6)

law of exponents; to the power of a negative, flip the fraction and make power positive

(c/1) ^ -1/6

(1/c)^ 1/6

1 / c^(1/6)

can't simplify further :)

ok, its pretty simple

u have C^1 ( C^(5/6) / C^2

u deal with the numerator so when u multiply components with same base u add their exponents
so C^1 (C^(5/6) u add 1+(5/6)= 11/6
so now u have

C^(11/6)/ C^2
and when you are dividing components with base base you subtract their exponents
so 11/6 - 2= -1/6
so u get C^(-1/6), now the negative just means u bring it to the denominator,
now this is the same as 1/ C^(1/6)
and there u go.
hope this helps

C(C^(5/6)/C^2 = C^(1+5/6)/C^2
= C^(11/6)/C^2
=C^(11/6-2)
=C^(-1/6)

(c(c^5/6)) / c^2
= (c/c^2)*(c^5/6)
= (c^-1)*(c^5/6)
=c^-1/6
=1/c^1/6