How do you solve x^2+5x+10=0 using square root property
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How do you solve x^2+5x+10=0 using square root property

[From: ] [author: ] [Date: 11-04-23] [Hit: ]
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x^2 + 5x + 10 = 0
(x + 5/2)^2 + 15/4 = 0
x = 1/2(-5 - i√15)
x = 1/2(-5 + i√15)

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The only way to solve this using the square root property is to complete the square.

By completing the square, we have:
x^2 + 5x + 10 = 0
==> x^2 + 5x = -10
==> x^2 + 5x + 25/4 = -10 + 25/4
==> (x + 5/2)^2 = -15/4.

Then, by taking the square root of both sides:
x + 5/2 = ±i√15/2 ==> x = (-5 ± i√15)/2.

I hope this helps!
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