Can you please check to see if I did my Algebra 2 homework correctly

Is the following function linear, or quadratic? Identify the linear, quadratic, and constant term.

y=(x+1)(6x-6)-6x^2

is it

A: linear function. linear term: -35x, constant term: 6
B: quadratic function, quadratic term: 6x^2, linear term: -35x, constant term: 6
C: Linear Function, linear term: 0x, constant term: -6
D: Quadratic term: -6x^2, linear term: 0x, Constant term: -6

I picked D. I don't know if I'm right, but I simplified the equation, and it was 6x^2-6. Am I right? Is the answer D?
______________________________________…


Simplify the Expression:

(2+5i)(-1+5i)

is it

A: -27+ 5i
B: 23+5i
C: -2+25i
D: -2+5i

I picked C. Am I right?
--------------------------------------…


Find a quadratic function to model the values in the table. Predict the value of y for x=6

(imagine the table)
the X's are -1, 0, 3
The Y's are 2, -2, 10

is it

A: y= -2x^2 + 2x - 2; 58
B: y= 2x^2 - 2x- 2; 60
C: y= 2x^2- 2x- 2; 58
D: y = -2x^2 + 2x +2; -58


I picked C. Am I right?

1. No, you expand the brackets (x+1) (6x-6) = 6x^2 + 6x -6x -6 = 6x^2 - 6
Then -6x^2 so all you're left with is -6. No x terms, no x^2 terms.

2. No, i's do not work like x's in algebra. Remember that i^2 = -1 and try again.

3. Yeah ya got that one right :)

1) c
2) a
3) c