Show that, if f:R → R is symmetric wit respect to 2 distinct vertical axes, then f is periodic.
Thank you.
Thank you.
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Let the axes be
x = a
x = b.
Then we have the following for every real x:
f(x) = f(2a-x)
f(x) = f(2b-x)
In particular, this shows:
f(x) = f(2a - x) = f(2b - (2a-x) ) = f(x + 2(b-a))
so that f is at least 2|b-a|-perioidic.
x = a
x = b.
Then we have the following for every real x:
f(x) = f(2a-x)
f(x) = f(2b-x)
In particular, this shows:
f(x) = f(2a - x) = f(2b - (2a-x) ) = f(x + 2(b-a))
so that f is at least 2|b-a|-perioidic.