Ok, so suppose we have vectors a and b.
2a = -3b
Find the value of m:
|b| = m|a|
Now, would the fact that a and b are now scalar, play any role in the value of m?
I am getting -2/3, but the book -> 2/3
2a = -3b
Find the value of m:
|b| = m|a|
Now, would the fact that a and b are now scalar, play any role in the value of m?
I am getting -2/3, but the book -> 2/3
-
Magnitude is always a positive quantity; the negative sign can be visualized as turning a vector into a new vector, antiparallel to the first one. This doesn't change the magnitude. That's why it's a 2/3. In the same vein, sqrt((-3)^2) = |-3| = 3.