Hi,
(x+11)² + 50 = 0
(x+11)² = -50
. ______ . . .___
√(x+11)² = √ -50
. . . . . . . . .__
x+11 = ±5i√ 2
. . . . . . . . . __
x = -11 ± 5i√ 2 <==ANSWER
I hope that helps!! :-)
(x+11)² + 50 = 0
(x+11)² = -50
. ______ . . .___
√(x+11)² = √ -50
. . . . . . . . .__
x+11 = ±5i√ 2
. . . . . . . . . __
x = -11 ± 5i√ 2 <==ANSWER
I hope that helps!! :-)
-
It depends what field you are working in.
With real numbers, you would proclaim "it has no roots" (it has no solution),
because:
square root property = a square is always "non-negative",
meaning that the value of anything squared can never be negative.
therefore the value of (x+11)^2 can NEVER be less than zero, whatever the value of x.
Adding a non-negative value to +50 can NEVER equal zero.
---
If you are working with complex numbers, you would solve it in the usual way:
(x+11)^2 + 50 = 0
(x + 11)^2 = -50
square root both sides
(x + 11) = =/- sqrt(-50)
x = -11 +/- sqrt(-50)
etc.
Here, the complex square root property would say that a negative square must come from an imaginary number (a number that is not "real").
With real numbers, you would proclaim "it has no roots" (it has no solution),
because:
square root property = a square is always "non-negative",
meaning that the value of anything squared can never be negative.
therefore the value of (x+11)^2 can NEVER be less than zero, whatever the value of x.
Adding a non-negative value to +50 can NEVER equal zero.
---
If you are working with complex numbers, you would solve it in the usual way:
(x+11)^2 + 50 = 0
(x + 11)^2 = -50
square root both sides
(x + 11) = =/- sqrt(-50)
x = -11 +/- sqrt(-50)
etc.
Here, the complex square root property would say that a negative square must come from an imaginary number (a number that is not "real").