hello,
log^2 x + log (x+1) = 7 / (log x - log 10)
x=?
---- by log^2 x i mean (log x)^2 ----
thanks
log^2 x + log (x+1) = 7 / (log x - log 10)
x=?
---- by log^2 x i mean (log x)^2 ----
thanks
-
log^2 x + log(x + 1) = 7/(log x - log 10)
[log^2 x + log (x + 1)](log x - log 10) = 7
log^3 x + log x log (x + 1) - log^2 x - log (x + 1) = 7
log^3 x - log^2 x + log x log (x + 1) - log (x + 1) - 7 = 0
x ≈ 122.0186
[log^2 x + log (x + 1)](log x - log 10) = 7
log^3 x + log x log (x + 1) - log^2 x - log (x + 1) = 7
log^3 x - log^2 x + log x log (x + 1) - log (x + 1) - 7 = 0
x ≈ 122.0186