MATH! i need help with this problem please

the difference between the squares of two consecutive odd numbers is 128. What is the product of the two integers?

Let the 2 consecutive odd numbers are (n-1) and (n+1).
(n+1)^2 - (n-1)^2 = 128
Expanding and simplifying the terms,
4n = 128
n = 32
The 2 odd numbers are 31 and 33.

(2x + 3)^2 - (2x + 1)^2 = 128

(2x + 3) * (2x + 1) = ?

(2x + 3)^2 - (2x + 1)^2 = 128
4x^2 + 12x + 9 - 4x^2 - 4x - 1 = 128
8x + 8 = 128
x + 1 = 16
x = 15

2x + 3 = 33
2x + 1 = 31

33 * 31 = (32 + 1) * (32 - 1) = 32^2 - 1^2 = 1024 - 1 = 1023

1023