Multiply both sides by q:
q(7q - 2) = 4/q * q
7q² - 2q = 4
Then, bring 4 to the left:
7q² - 2q - 4 = 0
Since the expression is not factorable, use quadratic formula, letting:
a = 7
b = -2
c = -4
So:
q = (-b ± √(b² - 4ac))/2a
= (2 ± √((-2)² -4*7*-4))/(2*7)
= (2 ± √(4 + 112))/14
= (2 ± √(116))/14
= (2 ± √(29*4))/14
= (2 ± 2√29)/14
= 2(1 ± √29)/14
= (1 ± √29)/7
I hope this helps!
q(7q - 2) = 4/q * q
7q² - 2q = 4
Then, bring 4 to the left:
7q² - 2q - 4 = 0
Since the expression is not factorable, use quadratic formula, letting:
a = 7
b = -2
c = -4
So:
q = (-b ± √(b² - 4ac))/2a
= (2 ± √((-2)² -4*7*-4))/(2*7)
= (2 ± √(4 + 112))/14
= (2 ± √(116))/14
= (2 ± √(29*4))/14
= (2 ± 2√29)/14
= 2(1 ± √29)/14
= (1 ± √29)/7
I hope this helps!