3^x + 6 =370 how do i solve

You would first subtract the 6, then use logarithms. So,
3^x+6=370
3^x=364
Log(3)x=Log(364)
x=Log(364)/Log3

x=5.378

Make sense?

3^x = 361 subtract 6 from both sides
logbase3 x = logbase3 361 log base 3 of both sides
x = log361/log3 change-of-base formula
x =(approximately) 5.360

3^x+6 = 370
3^x = 364
xln3 = ln364 (power rule)
x = ln364/ln3
x = 5.3678

3^x = 363
x = log-base3(363) = log(363)/log(3)

x = 5.365