Did I do these two math problems correctly
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Did I do these two math problems correctly

[From: ] [author: ] [Date: 11-04-29] [Hit: ]
-1. How much can it hold? That is simply asking what the volume of the object is.Now what is the volume formula for a cylinder? V = π * h * r^2 = area of base * height.Now the area of a circle (the base in our case) is C = π * r^2= π * (18 / 2)^2 = 81π.......
Q:
A tank has a cylindrical shape. The base has a diameter of 18m and the tank is 32m high. How much water can the tank hold?
My Work/answer:
PI(9)^2=PI(81)=254.46(32)= 8143.08 m^3

And also :)
Q:Prism with a rectangular base:
8in by 6 in
height 7 in
Whats the volume?
My work:
8(6)=48(7)=336ft^3

Thank you, and sorry for the trouble, even though I did it I can't help but always feel like I did it wrong :( Im pretty sure the 2nd one I did incorrectly.

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1. How much can it hold? That is simply asking what the volume of the object is.

Now what is the volume formula for a cylinder? V = π * h * r^2 = area of base * height.

Now the area of a circle (the base in our case) is C = π * r^2= π * (18 / 2)^2 = 81π.

We know height is 32m. Thus Volume = 81π * 32 = 2592π = 8 143.008 m^3.


2. Volume of a prism with a rectangular base = area of the triangle * length.

Area of triangle = base * height / 2 = 6 * 7 / 2 = 21 inches squared.

Volume = 21 in^2 * length = 21 in^2 * 8in = 168 in^3.

Now the volume of what you have is double of mine. The reason is because either you meant a rectangular prism (a box basically) which would have a volume of 336 in^3 or a prism (with a triangular head) and a rectangular base, which would have a volume of 168 in^3. Whichever one it is, you now have the answer. ;)

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