Help me with this math question..

I have this triange with the following meseaurments:

In triangle ABC: angle A is : 37.5, side b is: 5.6, side c is :15.2 and side a is : 11.2
also angle C is: 124.9

How would this triangle look like... can you guys show me a model or a sketch of it..

Thank you in advance :-)

You can calculate the height of the triangle
consider
Side (a) 11.2
Side b 5.6 ie 11.2/2
Side c 15.2

Angle A 37.5
Angle B 17.6
Angle C 124.9


Now, Perpendicular on C= simple algebric and triginometric calculation:
x+y 15.2
p x*(tan17.6) /* p for perpendicular from point c on side C
p y*(tan37.5) /* y is the distance between corner A and the point at which perpendicular intersects the side C; x= 15.2-y

x y*(tan37.5)/(tan17.6)
x 2.418y
x+y 15.2
3.418y 15.2
y 4.447045056
x 10.75295494
p 8.245365388

Now take a pencil and paper:
First draw the base line (side C)
Measure 10.75 units from left terminus of C
Draw a perpendicular from this point of length p= 8.245365388
Now join the points.

Just do it yourself. Draw each of the lines out on paper to the exact measurements (you could even make them in centimeters), then you could cut them out and reposition them in the shape of a triangle.

It will have three sides that are straight lines. I suggest google image for this.