Can you help with this pre algebra
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Can you help with this pre algebra

[From: ] [author: ] [Date: 11-04-27] [Hit: ]
35, 53, 41,Identify the third quartile for the data set.37, 48,......
Find the first quartile of the data set.
37, 48, 56, 35, 53, 41, 50

Identify the third quartile for the data set.
37, 48, 56, 35, 53, 41, 50

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According to Wikipedia, there are two commonly-used methods for dividing up a dataset into quartiles.

First, write the data in ascending order: 35, 37, 41, 48, 50, 53, 56. The median of this dataset is 48.

Quoting from the cited article (one or both of which should be in your text),

Method 1: Use the median to divide the ordered data set into two halves. Do not include the median into the halves. The lower quartile value is the median of the lower half of the data. The upper quartile value is the median of the upper half of the data.

This rule is employed by the TI-83 calculator boxplot and "1-Var Stats" functions.

With this method, the lower half of the data is 35, 37, 41. Its median is 37, so the first quartile (using Method 1) is 37. Similarly, the third quartile is 53.

The second method includes the median in both halves. Then the lower half is 35, 37, 41, 48. The median of this dataset is (37 + 41)/2 = 39 so, by this method, the lower quartile is 39. The median of the upper half is (50 + 53)/2 = 51.5, so the upper quartile is 51.5
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