Jodi poured herself a cold drink that had an initial temperature of 45 degrees F and immediately went outside to sunbathe where the temperature was a steady 93 degrees F. After 6 minutes, the temperature of the soda was 48 degrees F. Jodi had to run back in to answer the phone. What is the expected temperature of the soda after an additional 11 minutes?
I know the answer is 53.0 but I want to know how they got it. Can someone help?
I know the answer is 53.0 but I want to know how they got it. Can someone help?
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If we consider that temperature of cold drink rises at steady rate then
in 6 min it rose from 45 to 48 degree F = 3 degree F
Rise in 11 min will be in proportion. Let it be = x
Hence
Time Rise in temperature
6 min 3 degree F
11 min x degree F
Cross multiply
6*x = 11 *3
6x = 33
x = 33/6
x = 5.5
After 11 min the temperature of cold drink rose by 5.5 degree F
Hence new temperature
= 48 + 5.5
= 53.5 degree F
If the answer is 53.0 then i might have got it wrong somewhere. Can't figure out the mistake though :)
in 6 min it rose from 45 to 48 degree F = 3 degree F
Rise in 11 min will be in proportion. Let it be = x
Hence
Time Rise in temperature
6 min 3 degree F
11 min x degree F
Cross multiply
6*x = 11 *3
6x = 33
x = 33/6
x = 5.5
After 11 min the temperature of cold drink rose by 5.5 degree F
Hence new temperature
= 48 + 5.5
= 53.5 degree F
If the answer is 53.0 then i might have got it wrong somewhere. Can't figure out the mistake though :)