*Best Answer To First Correct* Trigonometric Identities Question! *Thumbs Up To All Answers*

Hey guys, I'm having trouble solving the following question:

Prove the following trigonometric identity:
1 + csc A = csc A (1 + Sin A)

Thanks for reading, please explain your steps and show your steps for 5 starts/best answer/thumbs up (The Works)

Thanks again.

1 + csc A = csc A (1 + Sin A)

Take the left hand side (LHS)
1 + cscA
= 1 + (1 / sinA)
= (sinA / sinA) + (1 / sinA)
= (sinA + 1) / sinA
= (1/sinA)(1 + sinA)
= cscA(1 + sinA)

LHS = RHS so it is proven


If you take the right hand side
csc A (1 + Sin A)
= (1/sinA) (1 + sinA)
= (1/sinA) + (sinA/sinA)
= (1/sinA) + 1
= 1 + cscA
RHS = LHS so it is proven

Identities used:
cscA = 1/sinA