How to use L'hopital's rule to solve limx->0 (sinx)(lnx)
Favorites|Homepage
Subscriptions | sitemap
HOME > Mathematics > How to use L'hopital's rule to solve limx->0 (sinx)(lnx)

How to use L'hopital's rule to solve limx->0 (sinx)(lnx)

[From: ] [author: ] [Date: 11-04-26] [Hit: ]
so you have a form 0 * infinity.To use LHopitals Rule, you need a form 0/0.Now its in the right form. You want to replace sin(x) by the derivative of sin(x), and 1/ln(x) by the derivative of 1/ln(x).......
As x->0, sin(x) ->0 and ln(x) -> infinity, so you have a form 0 * infinity.

To use L'Hopital's Rule, you need a form 0/0. Change it from sin(x) ln(x) to sin(x) / [1/ln(x)]

Now it's in the right form. You want to replace sin(x) by the derivative of sin(x), and 1/ln(x) by the derivative of 1/ln(x).
1
keywords: use,rule,limx,solve,gt,lnx,How,039,hopital,sinx,to,How to use L'hopital's rule to solve limx->0 (sinx)(lnx)
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .