X(x-1)=0 and x(x1)=0 BEST ANSWER

how do you set these quadratic equations up to? I can see the answer but i don't know how its set up. How does x=o etc. thank you yahoo!

x(x - 1) = 0

For this equation to be true, x has to = 1 or 0. Let's start with 1:

1(1 - 1) = 0
1(0) = 0
0 = 0

Now with x = 0:

0(0 - 1) = 0
0(-1) = 0
0 = 0

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x(x - 1) = 2...remove the parenthesis by multiplying the left side of the equation

x^2 - x = 2...subtract 2 from both sides of the equation

x^2 - x - 2 = 0...factor the left side of the equation

(x - 2)(x + 1) = 0

For this equation to be true, x has to equal 2 or -1. Let's start with 2:

(2 - 2)(2 + 1) = 0
(0)(3) = 0
0 = 0

Now let's try x = -1:

(-1 - 2)(-1 + 1) = 0
(-3)(0) = 0
0 = 0

Well x can equal 1 or zero.

x(x-1)=0
X has to be zero because if u multiply the (x-1)0 it will always be zero. No matter what the bracket equals to because zero times a number is always zero.

1 can also work because then 1-1 is 0 and zero times any number is zero.

Hope that makes sense! Good LuuucK! :)

If you are solving for x, then x is equal to 0 (multiplicity 3) and 1, unless by (X1) you mean x+1, in which case x = -1 and 0 has multiplicity 2

what you do is take each factor (in this case x, (x-1), x, and (x1)) and solve each for zero.