Which of the following statements is true about the series
∞
∑ (-1)^n cos(1/n)
n=0
a) the series is absolutely convergent
b) the series is conditionally convergent
c) the series is divergent
how do I go about showing the work for this?
∞
∑ (-1)^n cos(1/n)
n=0
a) the series is absolutely convergent
b) the series is conditionally convergent
c) the series is divergent
how do I go about showing the work for this?
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use limit,
when n--->infinity
1/n becomes zero
cos(0)=1
then for sufficiently large n you get
-1,+1,-1,+1, -1,+1,....
which goes on forever, it never converges to one value so it is divergent
when n--->infinity
1/n becomes zero
cos(0)=1
then for sufficiently large n you get
-1,+1,-1,+1, -1,+1,....
which goes on forever, it never converges to one value so it is divergent
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Note that this is an alternating series. An alternating series converges if:
(a) The non-alternating part forms a monotonically decreasing sequence
(b) The non-alternating part goes to zero as n --> infinity.
Since cos(1/n) fails to meet both of these requirements, the series diverges.
I hope this helps!
(a) The non-alternating part forms a monotonically decreasing sequence
(b) The non-alternating part goes to zero as n --> infinity.
Since cos(1/n) fails to meet both of these requirements, the series diverges.
I hope this helps!
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c) the series is divergent because as n->∞, the general term oscillates between 1 and -1
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This series diverges by n-th term test!