How to integrate (dx)2x+1/(x+2)^4(x-1)^4

(dx)2x+1/(x+2)^4(x-1)^4

= (dx)2x+1/[(x+2)(x-1)]^4

= (dx)2x+1/(x^2 + x -2)^4

put t = x^2 + x -2

=> dt = ( 2x + 1 )dx which is the numerator!

=>integral (dx)2x+1/(x+2)^4(x-1)^4

= integral dt/t^4

= -1/[3t^3] + c

= -1/[3(x^2+ x -2)^3] + c

which is the answer!!