Exponential growth function.Quite challenging.. BEST answer to first correct one
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Exponential growth function.Quite challenging.. BEST answer to first correct one

[From: ] [author: ] [Date: 11-04-24] [Hit: ]
How many people are initially infected?How many people are infected after 10 days?THANK YOU SO MUCH! I def need the help :)-Essentially, you have to find N at t=0 and at t=10. To do this you simply plug 0 and 10 into the equation for t.......
In a town whose pop. is 2,000, a disease creates an epidemic. The number of people 'N' infected 't' days after the disease has begun is given by the function

N(t)= (2000)/ ( 1+16.9e^-0.4t)

How many people are initially infected?
How many people are infected after 10 days?

THANK YOU SO MUCH! I def need the help :)

-
Essentially, you have to find N at t=0 and at t=10. To do this you simply plug 0 and 10 into the equation for t. My answer rounds to the nearest person.

N(0) = (2000)/(1+16.9e^(-0.4*0)) = 2000/(1+16.9e^0) = 2000/(1+16.9) = 2000/17.9 = 112 people.

N(10) = (2000)/(1+16.9e^(-0.4*10)) = 2000/(1+16.9e^-4) = 2000/1.3095 = 1527 people.
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