Can you please answer these 8 math problems? i will give 10 pts

1. graph each function just tell the coordinates

y=1/2x^2-1

2. y=-2x^2+3

3. solve each equation by finding square roots. if equation has no real solution, write no solution. if necessary round to the nearest tenth. HINT (you should have 2 answers for each)

x^2=49

4. 5x^2+25=90

5. 3x^2-27=0

6. 7x^2+8=15

7. 2x^2-6=26

8. x^2-400=0

1.) (0,-1);(2,1);(4,7);(-2,1);(-4,7)
2.) (0,3);(1,1);(-1,1);(2.-5);(-2,-5)
3.) x=7,-7
4.) x=√13,-√13
5.) x=3,-3
6.) x=1,-1
7.) x=4,-4
8.) x=20,-20

This confused me when I was doing quadratics so I just thought I'd mention when square rooting a number you should ALWAYS put a negative and positive sign outside the square root

1. To find y intercept make x = 0 and you find y = -1 to find x ints make y = 0 rearrange equation so x is on it's own that = +-√2

To find y int y=0-1 y= -1

To find x ints 0=1/2x^2 -1 1=1/2x^2 2=x^2 x =+-√2

so x ints =(+-√2,0) y ints =(0,-1)

To find turning point go half way between x coordinates that's 0 and put that in place of the x in the equation

so the turning point is the same as the y intercept (0, -1)

2.x ints = (+-√3/2,0) yint = (0,3) turning point = (0,-3)

3.x ints +-√49 =(7,0) (-7,0)

4.5x^2 + 25 = 90 5x^2 = 65 x^2 = 13 x= (3.6,0) (-3.6,0)

5.x = (3,0) (-3,0)

6.x= (1,0) (-1,0)

7. x = (4,0) (-4,0)

8. x = (20,0) (-20,0)

1. (0,-1),(2,1),(4,7),(-2,1),(-4,7)
2. (0,3),(1,1),(-1,1),(2.-5),(-2,-5)
number 3-8
3. x=7 or -7

4. 5x^2+25=90
5x^2=75
x^2=25
x=5 or -5

5. 3x^2-27=0
3x^2=27
x^2=9
x=3

6. 7x^2+8=15
7x^2=7
x^2 =1
x=1 or -1

7. 2x^2-6=26
2x^2=32
x^2=16
x=4 or -4

8. x^2-400=0
x^2=400
x= 20 or -20

Do your own homework!