How to solve? Derivatives and Limits
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How to solve? Derivatives and Limits

[From: ] [author: ] [Date: 12-02-12] [Hit: ]
As h->0 this becomes 22x - 6,So you got the a=11 part correct,......
Let f(x) be the function 11x^(2)-6x+10. Then the quotient (f(9+h)-f(9))/h can be simplified to ah+b. What is a and b?

For a I got 11 but I dont understand how b isn't -6. helppppppppppp!!!!

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( f(x+h) - f(x) ) / h = 11h + 22x - 6

As h->0 this becomes 22x - 6, which is the derivative of f(x)

Letting x=9 gives 11h + 22(9) - 6 = 11h + 192

So you got the a=11 part correct, and the second is just b=f'(9)=192
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