Question involving moles?

[From: ] [author: ] [Date: 14-03-06] [Hit: ]

Thanks!- Your equation is balanced so the next step is to convert 50 g of CaCO3 to moles.From the balanced equation, you make 1 mole of CaO per mole of CaCO3 so you know the moles of CaO you should have made.Multiply moles of CaO by its molar mass, that is the theoretical mass of CaO you should have made.......

50 g of CaCO3 is decomposed in the following reaction:
CaCO3 -----> CaO + CO2

7g of CaO is formed.

How do I calculate the percentage yield of CaO? Thanks!

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Your equation is balanced so the next step is to convert 50 g of CaCO3 to moles.

From the balanced equation, you make 1 mole of CaO per mole of CaCO3 so you know the moles of CaO you should have made.

Multiply moles of CaO by its molar mass, that is the theoretical mass of CaO you should have made.

percent yield = the actual amount of CaO (7 g) / theoretical mass of CaO * 100

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