22.65 L of a 0.02024 M permanganate solution was needed to react with the Fe2+ in sample of mass 1.1243g.

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22.65 L of a 0.02024 M permanganate solution was needed to react with the Fe2+ in sample of mass 1.1243g.

[From: ] [author: ] [Date: 13-11-05] [Hit: ]

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What is the mass of the Fe2+ in the sample and what is the % of Fe2+ in the sample?

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Are you sure that is 22.65 L? it should most likely be mL. So it would be .02265 L * .02024 moles/L = 0.000458436 moles * 55.85= 0.0256 g Fe/ 1.1243 = 2.277%..... That is if it is a 1/1 ratio between the solution and fe2+ and that you actually meant mL

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