A current of 4.59 A is pass through a Pb(NO3)2 solution. How long (in hours) would this current have to be app

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A current of 4.59 A is pass through a Pb(NO3)2 solution. How long (in hours) would this current have to be app

[From: ] [author: ] [Date: 13-04-02] [Hit: ]

70 g of lead?-at cation plate,7.7 = (207.19/2)(4.t = 0.......

A current of 4.59 A is pass through a Pb(NO3)2 solution. How long (in hours) would this current have to be applied to plate out 7.70 g of lead?

-

at cation plate,

Pb^2+ + 2e → Pb

w = Z i t/96500

7.7 = (207.19/2)(4.59)(3600t)/96500

t = 0.434 hours

1

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