Calculate activation energy

CO(g) + NO2(g) ? CO2(g) + NO(g)

Temperature (K) k (M-1s-1)
600. 0.028
650. 0.22
700. 1.3
750. 6.0
800. 23

Calculate Ea and A.

I dont now how the answer for Ea is 130 kj

You do this by plotting the temperature and the constant K values

ln(k)= -Ea/R (1/T) + ln (A)

R=8.314 J/mol*K

this is the The modified Arrhenius equation

note that This has the same form as an equation for a straight line

where y=mx + b

y=ln(k)
m= -Ea/R
x=1/T
b=ln(A)

On an Excel program you can plot these values and from the slope solve for the Ea and the intercept solve for A ( pre exponential factor)

for the first point on your graph

x1=ln0.028 x2=ln0.22
Y1=1/600 Y2=1/650
so on...

When you plot these values you will get from a squared minimun analysis the following
straight line equation

y = -16108x + 23.271
m=Slope = -16108=-Ea/R
b=intercept=A=23.271

Ea=-16108 mol* K(8.314J/mol*K)=-(-133921 J)=133.9 kJ

and A

b=lnA=23.271
A=Exp(23.271)=1.28*10^10