For the reaction 3 H2SO4 + Al(OH)3 -> 6 H2O + Al2(SO4)3,

[From: ] [author: ] [Date: 12-12-23] [Hit: ]

021/.15L = .......

what is molarity of Al(OH)3 solution if 150mL of it reacts w/50mL of 1.25 M H2SO4 solution? Please show work, greatly appreciate it!

50 ml x L/1000ml x 1.25 mol/L x mol Al(OH)3/ 3 mol H2SO4 = .021 mol

150ml x L/1000ml = .15L

M= .021/.15L = .14M

keywords: reaction,OH,the,For,SO,Al,gt,For the reaction 3 H2SO4 + Al(OH)3 -> 6 H2O + Al2(SO4)3,