Volume from Percent Ionization, HEEELLLLPPPPPPP!!!!!
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Volume from Percent Ionization, HEEELLLLPPPPPPP!!!!!

[From: ] [author: ] [Date: 12-11-29] [Hit: ]
! HELP-20 = (x / 0.x = [H^+] = 3.n(H^+) = (3.5x10^-2 M)(0.025 L) = 8.......
Question: Determine the volume of .125M NaOH required to titrate to the equivalence point of 25mL of a .175M of a weak acid that is 20% ionized
Answer is 35mL correct me if I'm wrong!!! HELP

-
20 = (x / 0.175)(100)

x = [H^+] = 3.5x10^-2 M

n(H^+) = (3.5x10^-2 M)(0.025 L) = 8.75x10^-4 mol <------ amount that reacts with NaOH

Volume = 8.75x10^-5 mol / 0.125 M = 7.0x10^-3 L = 7 mL

How did you get 35 mL?
1
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