Help finding the heat of solution
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Help finding the heat of solution

[From: ] [author: ] [Date: 12-11-19] [Hit: ]
So attempting to solve this question I did the following:(3g NAOH+100g H2O)*(12 degree C)*(4.18 the specific heat of water)= 5166 JIve tried a bunch of other things trying to get the right answer, but out of all of them I thought this made the most sense. If anyone could tell me where I went wrong that would be greatly appreciated.-5166 J / 4.100 g x 4.......
When 3.00 g of sodium hydroxide (NaOH) was dissolved in 100.00 g of water a value of 12.00 degree C was obtained for ΔT

Calculate the value (calories) for the heat of solution of 3.00 g of NaOH.

So attempting to solve this question I did the following: (3g NAOH+100g H2O)*(12 degree C)*(4.18 the specific heat of water)= 5166 J I've tried a bunch of other things trying to get the right answer, but out of all of them I thought this made the most sense. If anyone could tell me where I went wrong that would be greatly appreciated.

-
5166 J / 4.184 J/cal = 1235 calories

Normally 3 g of NaOH is not included:
100 g x 4.18 J/gC x 12 C = 5016 J
5016 J / 4.18 J/calorie = 1200 calories
or simply-
100 g x 1.00 cal/gC x 12C = 1200 calories
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