The weight of pure, dry AgCl obtained is..
A. 12.6 g
B. 287 g
C. 139 g
D. 54.2 g
E. 0.77 g
I am not sure how to work out this problem. It is on the practice quiz for my chem test next week.
Thanks!
A. 12.6 g
B. 287 g
C. 139 g
D. 54.2 g
E. 0.77 g
I am not sure how to work out this problem. It is on the practice quiz for my chem test next week.
Thanks!
-
The balanced equation of chemical RXN:
MgCl2 (aq) + 2Ag+ (aq) --------------> Mg (2+)(aq) + 2AgCl (s)
From the equation, 1 mol MaCl2 will give 2 mol AgCl.
So, The weight of pure, dry AgCl = (2 mol AgCl)*(143.32 g AgCl / 1 mol AgCl)
= 286.64 g ~ 287 g
MgCl2 (aq) + 2Ag+ (aq) --------------> Mg (2+)(aq) + 2AgCl (s)
From the equation, 1 mol MaCl2 will give 2 mol AgCl.
So, The weight of pure, dry AgCl = (2 mol AgCl)*(143.32 g AgCl / 1 mol AgCl)
= 286.64 g ~ 287 g