Ethylene glycol, C2H6O2, is used as antifreeze for automobile engines. If you want to produce 2.00 kg of ethylene glycol from the reaction of C2H4Cl2 and Na2CO3, what is the minimum amount of C2H4Cl2 that is needed?
C2H4Cl2(l) + Na2CO3(s) + H2O(l) ---->C2H6O2(l) + 2NaCl(aq) + CO2(g)
C2H4Cl2(l) + Na2CO3(s) + H2O(l) ---->C2H6O2(l) + 2NaCl(aq) + CO2(g)
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C2H4Cl2 + Na2CO3 + H2O → C2H6O2 + 2 NaCl + CO2
(2.00 kg C2H6O2) / (62.0681 g C2H6O2/mol) x (1/1) x (98.9597 g C2H4Cl2/mol) =
3.2 kg C2H4Cl2
(2.00 kg C2H6O2) / (62.0681 g C2H6O2/mol) x (1/1) x (98.9597 g C2H4Cl2/mol) =
3.2 kg C2H4Cl2