a sample of hydrogen occupies a volume of 1.20L at a pressure of 425 kPa. If the tempature of the gas is kept constant, what would the new volume of the gas be at 615 kPa?
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Boyle's Law: P1V1 = P2V2
P1 = 425 kPa
V1 = 1.20 L
P2 = 615 kPa
V2 = ?
425 x 1.20 = 615 x V
510 = 615V
V = 0.8293
Sig figs... 0.829 L
P1 = 425 kPa
V1 = 1.20 L
P2 = 615 kPa
V2 = ?
425 x 1.20 = 615 x V
510 = 615V
V = 0.8293
Sig figs... 0.829 L