Calculate the work done (in joules) by a chemical reaction if the volume increases from 3.2 L to 3.6 L ...
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Calculate the work done (in joules) by a chemical reaction if the volume increases from 3.2 L to 3.6 L ...

[From: ] [author: ] [Date: 12-04-12] [Hit: ]
4 = -1.1 L atm = 101.so W = -1.6 X 101.3 = -162.-ve sign shows that work is done by the system-Work done is P(V2-V1).......
...against a constant external pressure of 4.0 atm.

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W = -Pext X dV

Pext = 4 atm

dV = 3.6-3.2 = 0.4 L

W = - 4 X 0.4 = -1.6 L atm

1 L atm = 101.3 J

so W = -1.6 X 101.3 = -162.08 J

-ve sign shows that work is done by the system

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Work done is P(V2-V1)..As is pressure is constant.So its 4x(3.6-3.2)=1.6 lt-atm,,,In joules,its 1.6x101=161.6J.
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