Enthalpy change problem
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Enthalpy change problem

[From: ] [author: ] [Date: 12-04-09] [Hit: ]
calculate the ΔHf of N2H4(l).Can anyone tell me if this is correct?The part that was baffling me was the fact that within the equation, H2O is a liquid state, but the given enthalpy is gaseous. Am I just over thinking the problem or is there a reason for this?......
The ΔHr for the following reaction is shown.
N2H4(l) + O2(g) → 2 H2O(l) + N2(g)

ΔH = -623 kJ mol-1

Given that the ΔHf of H2O(g) is -286 kJ mol-1, calculate the ΔHf of N2H4(l).

My calculations say that the ΔHf of N2H4(l) = 51kJmol ^ -1
Can anyone tell me if this is correct?

The part that was baffling me was the fact that within the equation, H2O is a liquid state, but the given enthalpy is gaseous. Am I just over thinking the problem or is there a reason for this?

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Yes 51 is the right answer
1
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