Consider 4 L of a buffer composed of 2 M HCN and 3 M NaCN? How many moles of strong acid could this buffer withstand?
1. 0
2. 2
3. 12
4. 8
5. 3
1. 0
2. 2
3. 12
4. 8
5. 3
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NaCN + H+ -------> HCN + Na+
in order to be a buffer solution ...it must have both HCN (weak acid) and NaCN (salt)
no. of moles of NaCN = 3 X 4 = 12
as NaCN and acid reacts in 1:1 mole ratio so upto 12 moles of acid this buffer mixture could withstand because after that there will be only HCN in solution
in order to be a buffer solution ...it must have both HCN (weak acid) and NaCN (salt)
no. of moles of NaCN = 3 X 4 = 12
as NaCN and acid reacts in 1:1 mole ratio so upto 12 moles of acid this buffer mixture could withstand because after that there will be only HCN in solution