2 CH3SH + CO → CH3COSCH3 + H2S
If you mix 10.0 grams of CH3SH with excess CO and 8.65 grams of CH3COSCH3 is produced, what is the percent yield of the CH3COSCH3?
A. 92.3%
B. 68.1%
C. 83.2%
D. 46.2%
Please include work. I'm not sure how to approach this.
If you mix 10.0 grams of CH3SH with excess CO and 8.65 grams of CH3COSCH3 is produced, what is the percent yield of the CH3COSCH3?
A. 92.3%
B. 68.1%
C. 83.2%
D. 46.2%
Please include work. I'm not sure how to approach this.
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answer=a: 10g CH3SH, molar mass CH3SH= 48.04 g/mol gives ~0.20816 mol, molar ratio between CH3SH input and CH3COSCH3 is 2:1, so if you divide by 2 you get 0.10408 mol CH3COSCH3 produced. molar mass CH3COSCH3=90.06 g/mol * 0.10408=9.37 mols expected, 8.65/9.37 ~ 0.923
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