Im working on my chemistry and I have absolutely no idea how to do a problem that asks for the percent yield of a reaction. Please Help!!!
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To find percent yield, you need to find theoretical yield first off (You must calculate) and you must have an actual yield (You must actually perform the experiment) and multiply by 100% because it is a percent yield.
Here's an example problem.
CH4 + 2O2 -> CO2 + 2H2O
83.6g of CH4 is burned in an excess of O2. 73.2g of CO2 are collected.
A. Calculate the theoretical yield of CO2 in grams.
So you have 83.6g CH4 first off and you know O2 is the excess.
83.6g CH4 x 1molCH4 / 16.0g CH4 x 1mol CO2 / 1mol CH4 x 44.0g CO2 / 1mol CO2 = 230g CO2
B. Find the actual yield
Your actual yield is found in the problem. It is 73.2g CO2
C. Calculate the percent yield.
Percent yield is as follows: Percent yield: actual yield / theoretical yield x 100%
230gCO2 / 73.2g CO2 x 1.00 = 31.8%
Here's an example problem.
CH4 + 2O2 -> CO2 + 2H2O
83.6g of CH4 is burned in an excess of O2. 73.2g of CO2 are collected.
A. Calculate the theoretical yield of CO2 in grams.
So you have 83.6g CH4 first off and you know O2 is the excess.
83.6g CH4 x 1molCH4 / 16.0g CH4 x 1mol CO2 / 1mol CH4 x 44.0g CO2 / 1mol CO2 = 230g CO2
B. Find the actual yield
Your actual yield is found in the problem. It is 73.2g CO2
C. Calculate the percent yield.
Percent yield is as follows: Percent yield: actual yield / theoretical yield x 100%
230gCO2 / 73.2g CO2 x 1.00 = 31.8%
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percent yield = (actual yield) / (theoretical yield)