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Physics questions, please Help!!!

[From: ] [author: ] [Date: 12-01-13] [Hit: ]
28/9.8, = 6.56 secs. (Use vertical component only).Height attained = (v^2/2g),......
On level ground a shell is fired with an initial velocity of 73.5 m/s at 61.0 degrees above the horizontal and feels no appreciable air resistance.
Find the horizontal and vertical components of the shell's initial velocity.
How long does it take the shell to reach its highest point?
Find its maximum height above the ground
How far from its firing point does the shell land?
At its highest point, find the horizontal and vertical components of its acceleration
At its highest point, find the horizontal and vertical components of its velocity.
plz help

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Horizontal component = (cos 61) x 73.5, = 35.633m/sec.
Vertical component = (sin 61) x 73.5, = 64.28m/sec.

Time to max. height = (v/g), = 64.28/9.8, = 6.56 secs. (Use vertical component only).

Height attained = (v^2/2g), = 210.8 metres. (Ditto).

It will be in the air (2 x 6.56s) = 13.12 secs. Horizontal velocity component is 35.633m/sec., so range = (35.633 x 13.12) = 467.5 metres.

At highest point, horizontal and vertical components of acceleration = 0.

At highest point, horizontal velocity component = 35.633m/sec., and vertical component = 0.
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