(-1, 3) and perpendicular to y = -1/3x + 7.
y = 3x - 12
y = 3x + 6
y = 3x - 6
y = 3x
y = 3x - 12
y = 3x + 6
y = 3x - 6
y = 3x
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There is actually no question here !
Line
y = (-1/3) x + 7 <---------note brackets MUST be used.
m1 = - 1/3
m2 = 3
point (-1,3)
y - 3 = 3 ( x + 1 )
y = 3x + 6
Line
y = (-1/3) x + 7 <---------note brackets MUST be used.
m1 = - 1/3
m2 = 3
point (-1,3)
y - 3 = 3 ( x + 1 )
y = 3x + 6
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Thank you ---pleased to help.
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The slope of the line y = -x/3 + 7 or (y = -1/3x + 7) is -1/3.
The slope of the line perpendicular to y = -1/3x + 7 is 3. (reciprocal with opposite sign)
The equation of the perpendicular line that passes the point (-1,3) must be:
Y-y = m(X-x)
Y-3 = 3(X- [-1])
Y-3 = 3(X+1)
Y-3 = 3X + 3
Y = 3X +3 +3
Y = 3X + 6
y = 3x + 6.
The slope of the line perpendicular to y = -1/3x + 7 is 3. (reciprocal with opposite sign)
The equation of the perpendicular line that passes the point (-1,3) must be:
Y-y = m(X-x)
Y-3 = 3(X- [-1])
Y-3 = 3(X+1)
Y-3 = 3X + 3
Y = 3X +3 +3
Y = 3X + 6
y = 3x + 6.
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y = 3x + 6