How do I answer questions such as the following?
Predict the sign of the thermodynamic quantity requested for the system shown (Answer choices include : +, -, 0, or not enough information)
1. Delta S for HCL (g) + NH3 (g) ---> NH4Cl(s)
2. Delta H for Br2 (g) ---> 2Br(g)
3. Delta S(surroundings) for H2O (l) ---> H2O (g) at 100 degrees C, 1 atm
4. Delta S(universe) for H2O (l) ---> H2O(g) at 100 degrees C, 1 atm
5. Delta G for H2O (l) ----> H2O (g) at 50 degrees C, 1 atm
6. Delta G for H20 (l) ----> H2O (g) at 100 degrees C, 1 atm
Can someone please explain how they derived each answer? This is part of a study guide and I really want to understand the information. Thank you so much! :)
Predict the sign of the thermodynamic quantity requested for the system shown (Answer choices include : +, -, 0, or not enough information)
1. Delta S for HCL (g) + NH3 (g) ---> NH4Cl(s)
2. Delta H for Br2 (g) ---> 2Br(g)
3. Delta S(surroundings) for H2O (l) ---> H2O (g) at 100 degrees C, 1 atm
4. Delta S(universe) for H2O (l) ---> H2O(g) at 100 degrees C, 1 atm
5. Delta G for H2O (l) ----> H2O (g) at 50 degrees C, 1 atm
6. Delta G for H20 (l) ----> H2O (g) at 100 degrees C, 1 atm
Can someone please explain how they derived each answer? This is part of a study guide and I really want to understand the information. Thank you so much! :)
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1 negative because entropy decrease when gas goes to solid also there is less amount of moles. entropy is the state of disorder so if a gas which is in constant motion goes to solid, entropy decreases.
2 I am not sure for this one....
3 Well S of system is positive so I would say negative for surroundings.
4 at equilibrium S universe equals 0
5 I would say positive because enthalpy is positive and entropy is negative and at low temperatures it is positive.
6 I would say negative because enthalpy is positive and entropy is negative and at high temperatures it is negative.
2 I am not sure for this one....
3 Well S of system is positive so I would say negative for surroundings.
4 at equilibrium S universe equals 0
5 I would say positive because enthalpy is positive and entropy is negative and at low temperatures it is positive.
6 I would say negative because enthalpy is positive and entropy is negative and at high temperatures it is negative.