if #p = #e, charge = 0.. if charge = +1, you have 1 more p than e. if charge is -2, you have 2 more's than p
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first row..
#p + #n = Z
#p = Z - #n = 25-13=12
so atomic number = 12 and the symbol is Mg
since charge is +2, you must have 2 less electrons than protons = 12 - 2 = 10 electrons
2nd row.
Z = #p + #n
22 = 48 + 18? I don't think so
3rd row
Z = #p + #n
16 = #p + 16
#p = 0.. so you don't have any atoms. just 16 neutrons + 2 electrons... we call that typo soup
4th row
could be anything.
1p + 70n + 1e.
2p + 69n + 1e
2p + 69n + 2e
3p + 68n + 1e
3p + 68n + 2e
etc.
last row
Z = 82 + 125 = 207
atomic # = 82 ---> Pb
since you have 2 mole p's than e's.. charge is +2
giving you this
Sym.. Z.. #p... #e... #n.. .charge
Mg.... 25..12. .10 ... 13.. .2+
.. .. .. 22.. 48.. .... .. 18
.. .. .. 16.. .. .. .... ... 16.. .2-
.. ... .. 71.. ... .. .. .. .. . . .. .
Pb... .207.. 82.. .80..125.. 2+
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good luck