Q- For each of the following sets of compounds explain the variation in the DT (delta t) values in
terms of the specific intermolecular attractive forces present and their strength.You must identify the intermolecular attractive force primarily responsible for the observed trend in the DT values and how the strength of that attractive force varies among the compounds in that particular set.
Delta T values:
water- 7.39
methanol- 10.79
ethanol- 8.02
1-propanol- 8.91
2-propanol 7.16
1-butanol 4.79
acetone- 13.28
(a) methanol, ethanol, 1-propanol, and 1-butanol
(b) acetone and 2-propanol
(c) 1-propanol and 2-propanol
(d) water and methanol
terms of the specific intermolecular attractive forces present and their strength.You must identify the intermolecular attractive force primarily responsible for the observed trend in the DT values and how the strength of that attractive force varies among the compounds in that particular set.
Delta T values:
water- 7.39
methanol- 10.79
ethanol- 8.02
1-propanol- 8.91
2-propanol 7.16
1-butanol 4.79
acetone- 13.28
(a) methanol, ethanol, 1-propanol, and 1-butanol
(b) acetone and 2-propanol
(c) 1-propanol and 2-propanol
(d) water and methanol
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(a) Hydrogen bonding. Hydrogen bonding is more prevalent the smaller the molecule, and the ease with which the H in one molecule can "connect" with an oxygen in an adjacent molecule. The larger the molecules, the greater the difficulty in forming a hydrogen bond.
(b) The alcohol exhibits hydrogen bonding, the ketone does not.
(c) Hydrogen bonding for a primary alcohol is more prevalent than for a secondary alcohol.
(d) Water, with two hydrogen atoms can form more hydrogen bonds than can methanol.
(b) The alcohol exhibits hydrogen bonding, the ketone does not.
(c) Hydrogen bonding for a primary alcohol is more prevalent than for a secondary alcohol.
(d) Water, with two hydrogen atoms can form more hydrogen bonds than can methanol.